C++ concepts: BitmaskType
Defines a type that can be used to represent a set of constant values or any combination of those values. This trait is typically implemented by integer types, std::bitset, or enumerations (scoped and unscoped) with additional operator overloads.
[edit] Requirements
The bitmask type supports a finite number of bitmask elements, which are distinct non-zero values of the bitmask type, such that, for any pair Ci and Cj, Ci & Ci != 0 and Ci & Cj == 0. In addition, the value 0
is used to represent an empty bitmask, with no values set.
The bitwise operators operator&, operator|, operator^, operator~, operator&=, operator|=, and operator^= are defined for values of the bitmask type and have the same semantics as the corresponding built-in operators on unsigned integers would have if the bitmask elements were the distinct integer powers of two.
The following expressions are well-formed and have the following meaning for any BitsetType X
X |= Y | sets the value Y in the object X |
X &= ~Y | clears the value Y in the object X |
(X&Y) != 0 | indicates that the value Y is set in the object X |
Each representible bitmask element is defined as a constexpr value of the bitmask type.
[edit] Usage
The following standard library types satisfy BitmaskType
:
- std::ctype_base::mask
- std::ios_base::fmtflags
- std::ios_base::iostate
- std::ios_base::openmode
- std::regex_traits::char_class_type
- std::regex_constants::syntax_option_type
- std::regex_constants::match_flag_type
- std::launch,
Code that relies on some particular implementation option (e.g. int n = std::ios_base::hex), is nonportable because std::ios_base::fmtflags is not necessarily implicitly convertible to int.