std::has_virtual_destructor
From cppreference.com
Defined in header
<type_traits>
|
||
template< class T >
struct has_virtual_destructor; |
(since C++11) | |
If T
is a type with a virtual destructor, provides the member constant value
equal true. For any other type, value
is false.
Contents |
Inherited from std::integral_constant
Member constants
value
[static]
|
true if T has a virtual destructor , false otherwise (public static member constant) |
Member functions
operator bool |
converts the object to bool, returns value (public member function) |
operator()
(C++14)
|
returns value (public member function) |
Member types
Type | Definition |
value_type
|
bool
|
type
|
std::integral_constant<bool, value> |
[edit] Notes
If a class has a public virtual destructor, it can be derived from, and the derived object can be safely deleted through a pointer to the base object (C++FAQ Lite 20.7)
[edit] Example
Run this code
#include <iostream> #include <type_traits> #include <string> #include <stdexcept> int main() { std::cout << std::boolalpha << "std::string has a virtual destructor? " << std::has_virtual_destructor<std::string>::value << '\n' << "std::runtime_error has a virtual destructor? " << std::has_virtual_destructor<std::runtime_error>::value << '\n'; }
Output:
std::string has a virtual destructor? false std::runtime_error has a virtual destructor? true
[edit] See also
(C++11)(C++11)(C++11)
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checks if a type has a non-deleted destructor (class template) |