std::memcpy
From cppreference.com
Defined in header
<cstring>
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void* memcpy( void* dest, const void* src, std::size_t count );
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Copies count
bytes from the object pointed to by src
to the object pointed to by dest
.
If the objects overlap, the behavior is undefined. If the objects are not trivially copyable (e.g. scalars, arrays, C-compatible structs), the behavior is undefined.
Contents |
[edit] Parameters
dest | - | pointer to the memory location to copy to |
src | - | pointer to the memory location to copy from |
count | - | number of bytes to copy |
[edit] Return value
dest
[edit] Example
Run this code
#include <iostream> #include <cstring> int main() { char source[] = "once upon a midnight dreary..."; char dest[4]; std::memcpy(dest, source, sizeof dest); for (char c : dest) { std::cout << c << '\n'; } }
Output:
o n c e
[edit] See also
moves one buffer to another (function) |
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(C++11)
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copies a range of elements to a new location (function template) |
copies a range of elements in backwards order (function template) |
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(C++11)
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checks if a type is trivially copyable (class template) |
C documentation for memcpy
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