std::all_of, std::any_of, std::none_of
From cppreference.com
Defined in header
<algorithm>
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template< class InputIt, class UnaryPredicate >
bool all_of( InputIt first, InputIt last, UnaryPredicate p ); |
(1) | (since C++11) |
template< class InputIt, class UnaryPredicate >
bool any_of( InputIt first, InputIt last, UnaryPredicate p ); |
(2) | (since C++11) |
template< class InputIt, class UnaryPredicate >
bool none_of( InputIt first, InputIt last, UnaryPredicate p ); |
(3) | (since C++11) |
1) Checks if unary predicate
p
returns true for all elements in the range [first, last)
.
2) Checks if unary predicate
p
returns true for at least one element in the range [first, last)
.
3) Checks if unary predicate
p
returns true for no elements in the range [first, last)
.
Contents |
[edit] Parameters
first, last | - | the range of elements to examine |
p | - | unary predicate . The signature of the predicate function should be equivalent to the following: bool pred(const Type &a); The signature does not need to have const &, but the function must not modify the objects passed to it. |
Type requirements | ||
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InputIt must meet the requirements of InputIterator .
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UnaryPredicate must meet the requirements of Predicate .
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[edit] Return value
1) true if unary predicate returns true for all elements in the range, false otherwise. Returns true if the range is empty.
2) true if unary predicate returns true for at least one element in the range, false otherwise. Returns false if the range is empty.
3) true if unary predicate returns true for no elements in the range, false otherwise. Returns true if the range is empty.
[edit] Complexity
At most last
- first
applications of the predicate
[edit] Possible implementation
First version |
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template< class InputIt, class UnaryPredicate > bool all_of(InputIt first, InputIt last, UnaryPredicate p) { return std::find_if_not(first, last, p) == last; } |
Second version |
template< class InputIt, class UnaryPredicate > bool any_of(InputIt first, InputIt last, UnaryPredicate p) { return std::find_if(first, last, p) != last; } |
Third version |
template< class InputIt, class UnaryPredicate > bool none_of(InputIt first, InputIt last, UnaryPredicate p) { return std::find_if(first, last, p) == last; } |
[edit] Example
Run this code
#include <vector> #include <numeric> #include <algorithm> #include <iterator> #include <iostream> #include <functional> int main() { std::vector<int> v(10, 2); std::partial_sum(v.cbegin(), v.cend(), v.begin()); std::cout << "Among the numbers: "; std::copy(v.cbegin(), v.cend(), std::ostream_iterator<int>(std::cout, " ")); std::cout << '\n'; if (std::all_of(v.cbegin(), v.cend(), [](int i){ return i % 2 == 0; })) { std::cout << "All numbers are even\n"; } if (std::none_of(v.cbegin(), v.cend(), std::bind(std::modulus<int>(), std::placeholders::_1, 2))) { std::cout << "None of them are odd\n"; } struct DivisibleBy { const int d; DivisibleBy(int n) : d(n) {} bool operator()(int n) const { return n % d == 0; } }; if (std::any_of(v.cbegin(), v.cend(), DivisibleBy(7))) { std::cout << "At least one number is divisible by 7\n"; } }
Output:
Among the numbers: 2 4 6 8 10 12 14 16 18 20 All numbers are even None of them are odd At least one number is divisible by 7