hypot, hypotf, hypotl
Defined in header
<math.h>
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float hypotf( float x, float y );
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(1) | (since C99) |
double hypot( double x, double y );
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(2) | (since C99) |
long double hypotl( long double x, long double y );
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(3) | (since C99) |
Defined in header
<tgmath.h>
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#define hypot( x, y )
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(4) | (since C99) |
x
and y
, without undue overflow or underflow at intermediate stages of the computation.The value computed by this function is the length of the hypotenuse of a right-angled triangle with sides of length x
and y
, or the distance of the point (x,y)
from the origin (0,0)
, or the magnitude of a complex number x+iy
.
Contents |
[edit] Parameters
x | - | floating point value |
y | - | floating point value |
[edit] Return value
If no errors occur, the hypotenuse of a right-angled triangle, √x2
+y2
, is returned.
If a range error due to overflow occurs, +HUGE_VAL
, +HUGE_VALF
, or +HUGE_VALL
is returned.
If a range error due to underflow occurs, the correct result (after rounding) is returned.
[edit] Error handling
Errors are reported as specified in math_errhandling.
If the implementation supports IEEE floating-point arithmetic (IEC 60559),
- hypot(x, y), hypot(y, x), and hypot(x, -y) are equivalent
- if one of the arguments is ±0,
hypot
is equivalent to fabs called with the non-zero argument - if one of the arguments is ±∞,
hypot
returns +∞ even if the other argument is NaN - otherwise, if any of the arguments is NaN, NaN is returned
[edit] Notes
Implementations usually guarantee precision of less than 1 ulp (units in the last place): GNU, BSD, Open64.
hypot(x, y) is equivalent to cabs(x + I*y).
POSIX specifies that underflow may only occur when both arguments are subnormal and the correct result is also subnormal (this forbids naive implementations).
hypot(INFINITY, NAN) returns +∞, but sqrt(INFINITY*INFINITY+NAN*NAN) returns NaN.
[edit] Example
#include <stdio.h> #include <math.h> #include <errno.h> #include <fenv.h> #include <float.h> #pragma STDC FENV_ACCESS ON int main(void) { // typical usage printf("(1,1) cartesian is (%f,%f) polar\n", hypot(1,1), atan2(1,1)); // special values printf("hypot(NAN,INFINITY) = %f\n", hypot(NAN,INFINITY)); // error handling errno = 0; feclearexcept(FE_ALL_EXCEPT); printf("hypot(DBL_MAX,DBL_MAX) = %f\n", hypot(DBL_MAX,DBL_MAX)); if(errno == ERANGE) perror(" errno == ERANGE"); if(fetestexcept(FE_OVERFLOW)) puts(" FE_OVERFLOW raised"); }
Possible output:
(1,1) cartesian is (1.414214,0.785398) polar hypot(NAN,INFINITY) = inf hypot(DBL_MAX,DBL_MAX) = inf errno == ERANGE: Numerical result out of range FE_OVERFLOW raised
[edit] See also
(C99)(C99)
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computes a number raised to the given power (xy) (function) |
(C99)(C99)
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computes square root (√x) (function) |
(C99)(C99)(C99)
|
computes cubic root (3√x) (function) |
(C99)(C99)(C99)
|
computes the magnitude of a complex number (function) |
C++ documentation for hypot
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