std::make_tuple

 

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std::tuple

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make_tuple

tie

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Defined in header <tuple>
template< class... Types > tuple<VTypes...> make_tuple( Types&&... args );		(since C++11) (until C++14)
template< class... Types > constexpr tuple<VTypes...> make_tuple( Types&&... args );		(since C++14)

Creates a tuple object, deducing the target type from the types of arguments.

For each Ti in Types..., the corresponding type Vi in Vtypes... is std::decay<Ti>::type unless application of std::decay results in std::reference_wrapper<X> for some type X, in which case the deduced type is X&.

Parameters

args

-

zero or more arguments to construct the tuple from

Return value

A std::tuple object containing the given values, created as if by std::tuple<VTypes...>(std::forward<Types>(t)...).

Possible implementation

template <class T> struct special_decay { using type = typename std::decay<T>::type; };   template <class T> struct special_decay<std::reference_wrapper<T>> { using type = T&; };   template <class T> using special_decay_t = typename special_decay<T>::type;   template <class... Types> auto make_tuple(Types&&... args) { return std::tuple<special_decay_t<Types>...>(std::forward<Types>(args)...); }

Example

Run this code

#include <iostream>
#include <tuple>
#include <functional>
 
int main()
{
    auto t1 = std::make_tuple(10, "Test", 3.14);
    std::cout << "The value of t1 is "
              << "(" << std::get<0>(t1) << ", " << std::get<1>(t1)
              << ", " << std::get<2>(t1) << ")\n";
 
    int n = 1;
    auto t2 = std::make_tuple(std::ref(n), n);
    n = 7;
    std::cout << "The value of t2 is "
              << "(" << std::get<0>(t2) << ", " << std::get<1>(t2) << ")\n";
}

Output:

The value of t1 is (10, Test, 3.14)
The value of t2 is (7, 1)

tie	creates a tuple of lvalue references or unpacks a tuple into individual objects (function template)
forward_as_tuple	creates a tuple of rvalue references (function template)
tuple_cat	creates a tuple by concatenating any number of tuples (function template)