std::function::target_type
From cppreference.com
< cpp | utility | functional | function
const std::type_info& target_type() const;
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(since C++11) | |
Returns the type of the stored function.
Contents |
[edit] Parameters
(none)
[edit] Return value
typeid(T) if the stored function has type T
, otherwise typeid(void)
[edit] Exceptions
noexcept specification:
noexcept
[edit] Example
Run this code
#include <functional> #include <iostream> int f(int a) { return -a; } int main() { // fn1 and fn2 have the same type, but their targets do not std::function<int(int)> fn1(f), fn2([](int a) {return -a;}); std::cout << fn1.target_type().name() << '\n' << fn2.target_type().name() << '\n'; }
Possible output:
int (*)(int) main::$_0
[edit] See also
obtains a pointer to the stored target of a std::function (public member function) |