std::numeric_limits::denorm_min
From cppreference.com
< cpp | types | numeric limits
static T denorm_min();
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(until C++11) | |
static constexpr T denorm_min();
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(since C++11) | |
Returns the minimum positive subnormal value of the type T
, if std::numeric_limits<T>::has_denorm != std::denorm_absent, otherwise returns std::numeric_limits<T>::min(). Only meaningful for floating-point types.
Contents |
[edit] Return value
T
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std::numeric_limits<T>::denorm_min() |
/* non-specialized */ | T();
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bool | false |
char | 0 |
signed char | 0 |
unsigned char | 0 |
wchar_t | 0 |
char16_t | 0 |
char32_t | 0 |
short | 0 |
unsigned short | 0 |
int | 0 |
unsigned int | 0 |
long | 0 |
unsigned long | 0 |
long long | 0 |
unsigned long long | 0 |
float | 2-149 if std::numeric_limits<float>::is_iec559 == true |
double | 2-1074 if std::numeric_limits<double>::is_iec559 == true |
long double | /* implementation-defined */ |
[edit] Exceptions
(none) | (until C++11) |
noexcept specification:
noexcept |
(since C++11) |
[edit] Example
Demonstates the underlying bit structure of the denorm_min()
Run this code
#include <cstdint> #include <limits> #include <cassert> int main() { // the smallest subnormal value has sign bit = 0, exponent = 0 // and only the least significant bit of the fraction is 1 uint32_t denorm_bits = 0x0001; float denorm_float = reinterpret_cast<float&>(denorm_bits); assert(denorm_float == std::numeric_limits<float>::denorm_min()); }
[edit] See also
[static]
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returns the smallest finite value of the given type (public static member function) |
[static]
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identifies the denormalization style used by the floating-point type (public static member constant) |
[static] (C++11)
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returns the lowest finite value of the given type (public static member function) |