Template parameters and template arguments
Every template is parametrized by one or more template parameters, indicated in the parameter-list of the template declaration syntax:
template < parameter-list > declaration
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(1) | ||||||||
Each parameter in parameter-list may be one of
- non-type template parameter
- type template parameter
- template template parameter
Contents |
[edit] Non-type template parameter
type name(optional) | (1) | ||||||||
type name(optional) = default
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(2) | ||||||||
type ... name(optional)
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(3) | (since C++11) | |||||||
type is one of the following types (optionally cv-qualified, the qualifiers are ignored)
- integral type
- enumeration
- pointer to object or to function
- lvalue reference to object or to function
- pointer to member object or to member function
- std::nullptr_t (since C++11)
Array and function types may be written in a template declaration, but they are automatically replaced by pointer to data and pointer to function as appropriate.
When the name of a non-type template parameter is used in an expression within the body of the class template, it is an unmodifiable prvalue unless its type was an lvalue reference type.
[edit] Type template parameter
typename name(optional)
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(1) | ||||||||
class name(optional)
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(2) | ||||||||
typename|class name(optional) = default
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(3) | ||||||||
typename|class ... name(optional)
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(4) | (since C++11) | |||||||
In the body of the template declaration, the name of a type parameter is a typedef-name which aliases the type supplied when the template is instantiated.
There is no difference between the keywords class
and typename
in a type template parameter declaration.
[edit] Template template parameter
template < parameter-list > class name(optional)
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(1) | ||||||||
template < parameter-list > class name(optional) = default
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(2) | ||||||||
template < parameter-list > class ... name(optional)
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(3) | (since C++11) | |||||||
Unlike type template parameter declaration, template template parameter declaration can only use the keyword class
and not typename
.
In the body of the template declaration, the name of this parameter is a template-name (and needs arguments to be instantiated)
template<class T> class myarray {}; // two type template parameters and one template template parameter: template<class K, class V, template<typename> class C = myarray> class Map { C<K> key; C<V> value; };
[edit] Template arguments
In order for a template to be instantiated, every template parameter (type, non-type, or template) must be replaced by a corresponding template argument. For class templates, the arguments are either explicitly provided or defaulted. For function templates, the arguments are explicitly provided, defaulted, or deduced from context.
[edit] Template non-type arguments
The following limitations apply when instantiating templates that have non-type template parameters:
- For integral and arithmetic types, the template argument provided during instantiation must be a converted constant expression of the template parameter's type.
- For pointers to objects, the template arguments have to designate the address of an object with static storage duration and a linkage (either internal or external), or a constant expression that evaluates to the appropriate null pointer or std::nullptr_t value.
- For pointers to functions, the valid arguments are pointers to functions with linkage (or constant expressions that evaluate to null pointer values).
- For lvalue reference parameters, the argument provided at instantiation cannot be a temporary, an unnamed lvalue, or a named lvalue with no linkage.
- For pointers to members, the argument has to be a pointer to member expressed as &Class::Member or a constant expression that evaluates to null pointer or std::nullptr_t value.
In particular, this implies that string literals, addresses of array elements, and addresses of non-static members cannot be used as template arguments to instantiate templates whose corresponding non-type template parameters are pointers to data.
[edit] Template type arguments
A template argument for a type template parameter must be a type-id, which may name an incomplete type:
template <class T> class X { }; // class template struct A; // incomplete type typedef struct {} B; // type alias to an unnamed type int main() { X<A> x1; // OK, 'A' names a type X<A*> x2; // OK, 'A*' names a type X<B> x3; // OK, 'B' names a type }
[edit] Template template arguments
A template argument for a template template parameter must be an id-expression which names a class template or a template alias.
When the argument is a class template, only the primary template is considered when matching the parameter. The partial specializations, if any, are only considered when a specialization based on this template template parameter happens to be instantiated.
template<class T> class A { // primary template int x; }; template<class T> class A<T*> { // partial specialization long x; }; // class template with a template template parameter V template< template<typename> class V> class C { V<int> y; // uses the primary template V<int*> z; // uses the partial specialization }; C<A> c; // c.y.x has type int, c.z.x has type long
To match a template template argument A
to a template template parameter P
, each of the template parameters of A
must match corresponding template parameters of P
. If P
's parameter list includes a parameter pack, zero or more template parameters (or parameter packs) from A
's template parameter list are matched by it.
template<class T> struct eval; // primary template template< template<class, class...> class TT, class T1, class... Rest> struct eval<TT<T1, Rest...>> {}; // partial specialization of eval template <class T1> struct A; template <class T1, class T2> struct B; template <int N> struct C; template <class T1, int N> struct D; template <class T1, class T2, int N = 17> struct E; eval<A<int>> eA; // OK: matches partial specialization of eval eval<B<int, float>> eB; // OK: matches partial specialization of eval eval<C<17>> eC; // error: C does not match TT in partial specialization because // TT's first parameter is a type template parameter, // while 17 does not name a type eval<D<int, 17>> eD; // error: D does not match TT in partial specialization // because TT's second parameter is a type parameter pack, // while 17 does not name a type eval<E<int, float>> eE; // error: E does not match TT in partial specialization // because E's third (default) parameter is a non-type
[edit] Default template arguments
Default template arguments are specified in the parameter lists after the = sign. Defaults can be specified for any kind of template parameter (type, non-type, or template), but not to parameter packs.
If the default is specified for a template parameter of a primary class template, each subsequent template parameter must have a default argument, except the very last one may be a template parameter pack. In a function template, a parameter pack may be followed by more type parameters only if they have defaults or can be deduced from the function arguments.
Default parameters are not allowed
- in the out-of-class definition of a member template (they have to be provided in the declaration inside the class body)
- in friend class template declarations
On a friend function template declaration, default template arguments are allowed only if the declaration is a definition, and no other declarations of this function appear in this translation unit.
Default template arguments that appear in the declarations and the definition are merged similarly to default function arguments:
template<class T1, class T2 = int> class A; template<class T1 = int, class T2> class A; // the above is the same as the following: template<class T1 = int, class T2 = int> class A;
But the same parameter cannot be given default arguments twice in the same scope
template<class T = int> class X; template<class T = int> class X { /* ... */ }; // error
The template parameter lists of template template parameters can have their own default arguments, which are only in effect where the template template parameter itself is in scope:
// class template, with a type template parameter with a default template <class T = float> struct B {}; // template template parameter T has a parameter list, which // consists of one type template parameter with a default template <template <class = float> class T> struct A { void f(); void g(); }; // out-of-body member function template definitions template <template <class TT> class T> void A<T>::f() { T<> t; // error - TT has no default in scope } template <template <class TT = char> class T> void A<T>::g() { T<> t; // OK, t is T<char> }
Member access for the names used in a default template parameter is checked at the declaration, not at the point of use:
class B {}; template <class T> class C { protected: typedef T TT; }; template <class U, class V = typename U::TT> class D : public U {}; D<C<B>>* d; // access error, C::TT is protected
[edit] Examples
[edit] Non-type template parameters
#include <iostream> // simple non-type template parameter template<int N> struct S { int a[N]; }; template<const char*> struct S2 {}; // complicated non-type example template < char c, // integral type int (&ra)[5], // lvalue reference to object (of array type) int (*pf)(int), // pointer to function int (S<10>::*a)[10] // pointer to member object (of type int[10]) > struct Complicated { // calls the function selected at compile time // and stores the result in the array selected at compile time void foo(char base) { ra[4] = pf(c - base); } }; // S2<"fail"> s2; // Error: string literal cannot be used char okay[] = "okay"; // static object with linkage // S2< &okay[0] > s2; // Error: array element has no linkage S2<okay> s2; // works int a[5]; int f(int n) { return n;} int main() { S<10> s; // s.a is an array of 10 int s.a[9] = 4; Complicated<'2', a, f, &S<10>::a> c; c.foo('0'); std::cout << s.a[9] << a[4] << '\n'; }
Output:
42
This section is incomplete Reason: more examples |