reinterpret_cast conversion
Converts between types by reinterpreting the underlying bit pattern.
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[edit] Syntax
reinterpret_cast < new_type > ( expression )
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Returns a value of type new_type
.
[edit] Explanation
Unlike static_cast, but like const_cast, the reinterpret_cast expression does not compile to any CPU instructions. It is purely a compiler directive which instructs the compiler to treat the sequence of bits (object representation) of expression as if it had the type new_type.
Only the following conversions can be done with reinterpret_cast, except when such conversions would cast away constness or volatility.
expression
. (since C++11)
T1
can be converted to pointer to object of another type cv T2
. This is exactly equivalent to static_cast<cv T2*>(static_cast<cv void*>(expression)) (which implies that if T2
's alignment requirement is not stricter than T1
's, the value of the pointer does not change and conversion of the resulting pointer back to its original type yields the original value). In any case, the resulting pointer may only be dereferenced safely if allowed by the type aliasing rules (see below) T1
can be converted to reference to another type T2
. The result is an lvalue or xvalue referring to the same object as the original lvalue, but with a different type. No temporary is created, no copy is made, no constructors or conversion functions are called. The resulting reference can only be accessed safely if allowed by the type aliasing rules (see below)T1
can be converted to a pointer to another member object of another class T2
. If T2
's alignment is not stricter than T1
's, conversion to the original type yields the original value, otherwise the resulting pointer cannot be used safely.As with all cast expressions, the result is:
- an lvalue if new_type is an lvalue reference type or an rvalue reference to function type;
- an xvalue if new_type is an rvalue reference to object type;
- a prvalue otherwise.
[edit] Keywords
[edit] Type aliasing
When a pointer or reference to object of type T1
is reinterpret_cast
(or C-style cast) to a pointer or reference to object of a different type T2
, the cast always succeeds, but the resulting pointer or reference may only be accessed if one of the following is true:
- T2 is the (possibly cv-qualified) dynamic type of the object
- T2 and T1 are both (possibly multi-level, possibly cv-qualified at each level) pointers to the same type T3 (since C++11)
- T2 is the (possibly cv-qualified) signed or unsigned variant of the dynamic type of the object
- T2 is an aggregate type or a union type which holds one of the aforementioned types as an element or non-static member (including, recursively, elements of subaggregates and non-static data members of the contained unions): this makes it safe to cast from the first member of a struct and from an element of a union to the struct/union that contains it.
- T2 is a (possibly cv-qualified) base class of the dynamic type of the object
- T2 is char or unsigned char
If T2 does not satisfy these requirements, accessing the object through the new pointer or reference invokes undefined behavior. This is known as the strict aliasing rule and applies to both C++ and C programming languages.
Note that many compilers implement disable this rule, as a non-standard language extension, if the wrong-type access is made through the inactive member of a union.
Also note that this set of rules is more strict than the equivalent rules in the C programming language: C allows access through a pointer to any compatible type. C++ has no compatible types and does not allow access through a pointer or reference to a layout-compatible type if it doesn't satisfy any of the rules listed above (although access to its member may be allowed)
[edit] Example
Demonstrates some uses of reinterpret_cast:
#include <cstdint> #include <cassert> #include <iostream> int f() { return 42; } int main() { int i = 7; // pointer to integer and back uintptr_t v1 = reinterpret_cast<uintptr_t>(&i); // static_cast is an error std::cout << "The value of &i is 0x" << std::hex << v1 << '\n'; int* p1 = reinterpret_cast<int*>(v1); assert(p1 == &i); // pointer to function to another and back void(*fp1)() = reinterpret_cast<void(*)()>(f); // fp1(); undefined behavior int(*fp2)() = reinterpret_cast<int(*)()>(fp1); std::cout << std::dec << fp2() << '\n'; // safe // type aliasing through pointer char* p2 = reinterpret_cast<char*>(&i); if(p2[0] == '\x7') std::cout << "This system is little-endian\n"; else std::cout << "This system is big-endian\n"; // type aliasing through reference reinterpret_cast<unsigned int&>(i) = 42; std::cout << i << '\n'; }
Possible output:
The value of &i is 0x7fff352c3580 42 This system is little-endian 42
[edit] See also
const_cast conversion | adds or removes const |
static_cast conversion | performs basic conversions |
dynamic_cast conversion | performs checked polymorphic conversions |
explicit casts | permissive conversions between types |
standard conversions | implicit conversions from one type to another |